Question

A cow tethered with a rope of length 28 m at the center rectangular field of length 66 m breadth 50 m . Find the area of the land that the cow cannot graze ?
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Answer 1

AnSwer -:

The area of land that cow cannot graze

is-: 836 m^2

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Explanation-:

Area of Rectangle -:

“A= l x b”

A = Area

L = length

B = Breadth

Area of the circle ⭕️ -:

“A = π r^2”

A = Area

π = 22/7 or 3.14

R = Radius

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Given,

A cow tethered with a rope of length at

the centre of rectangular field

= 28 m

The length of rectangle = 66 m

The breadth of rectangle is = 50 m

To find ,

Area of the land that cow cannot graze.

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Area of the circle ⭕️

or

area of the land that cow can graze


Area of the circle ⭕️ -:

“A = π r^2”

A = Area

π = 22/7 or 3.14

R = Radius = 28 m

Now ,

π 28^2

22/7 x 28 x 28

= 2464 m^2

Area of the land that cow can graze -:

2464 m^2


Now ,

Area of Rectangle -:

“A= l x b”

A = Area

L = length = 66m

B = Breadth =50 m

66 x 50

= 3,300 m^2

Area of rectangle = 3,300 m^2

Now ,

Area of the land that cow cannot graze-:

Area of rectangle — Area of that cow

can graze

Area of rectangle = 3,300 m^2

Area of the land that cow can graze -:

2464 m^2

3,300 — 2464

= 836 m^2

Hence

The area of land that cow cannot graze

is-: 836 m^2


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