A crane is lifting a body to a height 'h' in time 't'. Find the relation between the power of crane to the speed at which it is lifting the object.
Explain with complete calculations & justifications.
Points : 15 ☺
Attachments:
Answers
Answered by
8
potential energy of body = -mgh
where m is the mass of body , g is acceleration due to gravity and h is height of body from ground level.
now,
potential energy of crane = -(potential energy of body ).
so ,
potential energy of crane = mgh
we also know,
power = energy/time
so, power of crane = energy of crane /time taken to consume energy
= mgh/t
=mg(h/t)
h/t is height of object per unit time e.g
speed of object lifting upward =h/t (let V)
so ,
power = mgV
where m is the mass of body , g is acceleration due to gravity and h is height of body from ground level.
now,
potential energy of crane = -(potential energy of body ).
so ,
potential energy of crane = mgh
we also know,
power = energy/time
so, power of crane = energy of crane /time taken to consume energy
= mgh/t
=mg(h/t)
h/t is height of object per unit time e.g
speed of object lifting upward =h/t (let V)
so ,
power = mgV
abhi178:
have you understand govind
Answered by
8
Let the crane lifts a body of mass 'm' to height 'h' in time 't' .
Then Work Done by Crane = mgh
where g is acceleration due to gravity .
Further ;
Power(P) = (Work Done) / (time taken)
P= mgh/t
=> P = mg ×(h/t)
here( h/t) is the speed ( say 'v')by which the crane is lifting the body .
=> P = mgv
________________
hope it helps!
Then Work Done by Crane = mgh
where g is acceleration due to gravity .
Further ;
Power(P) = (Work Done) / (time taken)
P= mgh/t
=> P = mg ×(h/t)
here( h/t) is the speed ( say 'v')by which the crane is lifting the body .
=> P = mgv
________________
hope it helps!
Similar questions
Psychology,
8 months ago
Chemistry,
8 months ago