A crane uses a 1, 875 N force to lift a car to a height of 17 m. a. How much work is done on the car? b. The crane's hydraulic motor does a 108 kJ work on the cable in the crane. What is the efficiency of the crane?
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a) W=2200*25=55000Joule b) Efficiency=55000/110000=0.5 c) Potential energy= 2200*25=55000 J
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Answer:
work done = 31875J
efficiency of moror = 29.51%
Explanation:
work = force x displacement
= 1875 x 17 = 31875 J
Cranes motor does work = 108KJ
work efficiency = output /input * 100
= (31875/108000)*100
= 29.51%
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