Polynomial p is defined by
p(x)=x3+5x2−2x−24p
has a zero at x = 2. Factor p completely and find its zeros.
Answers
solution
★ p(x) has a zero at x = 2 and therefore x - 2 is a factor of p(x).
★ Divide p(x) by x - 2
→ p(x) / (x - 2) = (x² + 5 x² - 2 x - 24) / (x- 2)x2 + 7 x + 12
★Using the division above, p(x) may now be written in factored form as follows:
→ p(x) = (x - 2)(x2 + 7 x + 12)
Factor the quadratic expression
→ x² + 7 x + 12.
→ p(x) = (x - 2)(x + 3)(x + 4)
The zeros are found by solving the equation.
→ p(x) = (x - 2)(x + 3)(x + 4) = 0
For p(x) to be equal to zero, we need to have
→ x - 2 = 0 , or x + 3 = 0 , or x + 4 = 0
Solve each of the above equations to obtain the zeros of p(x).
→ x = 2 , x = - 3 and x = -4
Q..Polynomial p is defined by
p(x)=x3+5x2−2x−24p
has a zero at x = 2. Factor p completely and find its zeros.
p(x) has a zero at x = 2 and therefore x - 2 is a factor of p(x).
⚘Divide p(x) by x - 2
→ p(x) / (x - 2) = (x² + 5 x² - 2 x - 24) / (x- 2)x2 + 7 x + 12
⚜Using the division above, p(x) may now be written in factored form as follows:
→ p(x) = (x - 2)(x2 + 7 x + 12)
Factor the quadratic expression
→ x² + 7 x + 12.
→ p(x) = (x - 2)(x + 3)(x + 4)
The zeros are found by solving the equation.
→ p(x) = (x - 2)(x + 3)(x + 4) = 0
For p(x) to be equal to zero, we need to have
→ x - 2 = 0 , or x + 3 = 0 , or x + 4 = 0
Solve each of the above equations to obtain the zeros of p(x).
→ x = 2 , x = - 3 and x = -4
⚜⚜⚜⚜⚜⚜⚜⚘⚘⚘⚘⚘⚘⚘⚜⚜⚜⚜⚜⚜⚜⚘⚘⚘⚘⚘⚘⚘⚘
#keep a smile always....☺️☺️
#And take take.....
# love u siso....
# wish ki tu mujhe bhulagi nahi khabi bhi........❤️
....shivi.....
miss busy...