A crankshaft and a flywheel have a total moment of inertia of 4,8kg/m^2 and rotate at 1200rev/min.The clutch engages the stationary driveshaft which has a moment of inertia of 5.2kg/m^2.caculate (a)all nodular momentum of the crankshaft and flywheel (b)common velocity of the combined system (c)angular impulse of the crankshaft and flywheel?
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torque=moment of inertia*angular acceleration
angular acceleration=angular speed/time
30/15 = 2
moment of inertia=2
so,torque =4Nm
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angular acceleration=angular speed/time
30/15 = 2
moment of inertia=2
so,torque =4Nm
hope this answer is correct....and will help you
PLEASE MARK ME AS BRAINLIST
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