A cricket ball is throen at s dpeed 30 m/s in a direction30° above the horizental. Thr time takem bybthe ball to return the same level is
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2
Maximum height = (V sin0)² / 2g
= (28 sin30)²/ 2 x 9.8
= 14 x 14 / 2 x 9.8
= 10m
time taken to return to the same level
=2 v sin0/ g
= 2 x 28 x sin30/ 9.8
= 2 x 28 x 1/ 2 x 9.8
= 2.9 sec
distance from thrower to where the ball returns
= v² sin 2Ф/ g
= 28 x 28 x sin60/ 9.8
= 69.3 m
= (28 sin30)²/ 2 x 9.8
= 14 x 14 / 2 x 9.8
= 10m
time taken to return to the same level
=2 v sin0/ g
= 2 x 28 x sin30/ 9.8
= 2 x 28 x 1/ 2 x 9.8
= 2.9 sec
distance from thrower to where the ball returns
= v² sin 2Ф/ g
= 28 x 28 x sin60/ 9.8
= 69.3 m
Answered by
0
Answer:
t=3 sec
Explanation:
Using formula of Projectile motion:
t=(2vi sin 30)/g
=(2*30*1/2)/10
=30/10
=3sec.....................(ANSWER
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