Question

A cricket ball is thrown at speed of some in a directly
making an angle 30 with horizontal caluclate
A. Max height. B. Time taken to return to earth
c. Distance from lower to the point where ball returns
to earth​

Answer 1

Answer:

solved

Explanation:

A. Max height =  u²sin²∝/2g =  u²sin²30°/8g =  u²/80 m.

B. Time taken to return to earth  = 2u sin∝/g = u/10 sec.

c. Distance from lower to the point where ball returns

to earth​ = range = u²sin2∝/g = u²sin60°/g = √3u²/20 m.