a cricket ball is thrown up with a speed of 19.6m p s . the max. height it can reach is?
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v =19.6 m/s
u =0
a = 9.8m/s^2
v^2 =u^2 + 2as
or,( 19.6*19.6) =0 +2(9.8)s
or, s = 19.6 m
Thus, the maximum height reached is 19.6m
Hope it helps!
u =0
a = 9.8m/s^2
v^2 =u^2 + 2as
or,( 19.6*19.6) =0 +2(9.8)s
or, s = 19.6 m
Thus, the maximum height reached is 19.6m
Hope it helps!
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