Physics, asked by GargiP738, 1 year ago

a cricket ball mass 0.15kg is moving with a velocity of 1.2m/s find the impulse on the ball and force applied by the player if he is able to stop the ball in 0.18s

Answers

Answered by JunaidMirza
5
Impulse = Change in momentum
= m Δv
= 0.15 kg × (1.2 m/s - 0 m/s)
= 0.18 kg m/s

Force = Impulse / Time
= (0.18 kg m/s) / 0.18 s
= 1 N
Similar questions