Question

A cricket ball of mass 0.20 kg is moving with a velocity of 1.2 m/s. Find the average force applied by the player if he is able to stop the ball in 0.10 s?​

Answer 1

Answer:

Required average force applied is 1.2 N.

Explanation:

Given:

• Mass (m) = 0.20 kg
• Initial velocity (u) = 1.2 m/s
• Final velocity (v) = 0
• Time (t) = 0.10 s

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To find:

Average force applied.

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Solution:

We know that,

Acceleration = (v – u)/t

= (0 – 1.2)/0.10

= –12 m/s²

Now as we know that,

Force = mass × acceleration

F = m × a

F = ma

Now substitute the values, we get

F = 0.2 × –12 = –2.4 N

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∴ Required force = –2.4 N

Answer 2

Given:-

• A cricket ball of mass 0.20 kg is moving with a velocity of 1.2 m/s.
• He $is$able to stop the ball in 0.10 s

To find:

• Find the average force applied by the player.

Solution:

In order to find the force we need to know acceleration first,

So, as we know

Acceleration = (v – u)/t

where,

⇒ Initial velocity = " u "= 1.2 m/s

⇒ Final velocity = " v " = 0

⇒ Time = " t " = 0.10 s

Now, let's substitute the values

= (0 – 1.2)/0.10

= –12 m/s²

Now we got acceleration

So,

⇒ F = m × a

Here,

• Force = " f "
• mass = " m "
• acceleration = " a "

Now,

⇒ F = 0.2 × –12

⇒ F = ( –2.4 N)

Therefore,

The average force applied by the player is (–2.4 N)

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