a cricket ball of mass 0.4kg moving with a velocity of 72km/h is brought to rest by a player. what is magnitude of the average force exerted by the player?
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Let us assume the ball is stopped in t seconds.
v = u + at 0 = - 72 * 5/18 + a t a = 20 / t m/sec²
average Force = m * a = 0.4 * 20 / t = 8 / t Newtons.
If the ball is stopped in 0.2 seconds, average Force = 40 Newtons
average force depends on the time duration.
v = u + at 0 = - 72 * 5/18 + a t a = 20 / t m/sec²
average Force = m * a = 0.4 * 20 / t = 8 / t Newtons.
If the ball is stopped in 0.2 seconds, average Force = 40 Newtons
average force depends on the time duration.
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3
Answer:
ANSWER is 40 Newton and please mark as brainlist answer
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