Question

a cricket ball of mass 0.5 kg strickes a bat normally with a velocity 30 Ms -1 and rebounds with a velocity 20 Ms -1 in the opposite direction, calculate the impulse of the force exerted by the ball on the bat ?​

Answer 1

Answer:

Magnitude of impulse, J = 25 kg-m/s

Explanation:

Given that,

Mass of the ball, m = 0.5 kg

Initial velocity of the ball, u = 30 m/s

Final velocity of the ball, v = -20 m/s (as it rebounds)

We need to find the impulse of force exerted by the ball on the bat. Let it is equal to J. The change in momentum is equal to the impulse. Mathematically,

J = -25 kg-m/s

So, the impulse exerted by the ball on the bat is 25 kg-m/s. Hence, this is the required solution.

Answer 2

Answer:

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