A cricket ball of mass 100 g has an initial velocityū = (2+3j
) m's and a final velocity v=-(2î+3ị) mis after being hit by bat. The change
in momentum (in kg m s) of the ball is
O-(0.31 +1:21)
O-(0.41 +0.63
0 - (4i +6] )
Zero
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Answer:
1/10[-(4i+6j) ]
Explanation: change in momentum= m(vf-vi)
100/1000[-(2i+3j) -(2i+3j) ]
= 1/10[-(4i+6j) ]
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