Question

Given the following equation, determine the solutions when y=0 for the function:
y= -x^2 – 2x + 8​

Answer 1

Answer:

x = 2, -4

Step-by-step explanation:

-x^2 – 2x + 8 = 0

by multiplying -1 on both sides,

x² + 2x - 8 = 0

x² + 4x - 2x - 8 = 0

x (x + 4) -2 (x + 4) = 0

(x - 2) (x + 4) = 0

x - 2 = 0

x = 2

and

x + 4 = 0

x = -4