Question

A cricket ball of mass 100g moving with a speed of 30m/s is brought to rest by a player. Then find the change in momentum.​

Answer 1

solution:given m=100g=0.1kg

v= 30m/s

initial momentum (p') = mv =0.1×30=3kg m/s

final momentum (p") the ball is now stopped by player so the velocity is zero so the momentum is also zero

from substrating we finds that the change in momentum is 3kg m/s

Answer 2

Explanation:

We know that,

momentum(P) = mass × velocity

(or)

P = mv

Initial momentum(Pᵢ) = m₁v₁

m₁ = 100g = 0.1 kg

v₁ = 30 m/s

Pᵢ = (0.1)(30)

= 3kg m/s

Final momentum(Pf) = m₂v₂

m₂ = 0.1 kg

As it is bougth to rest,

v₂ = 0

Pf = (0.1)(0)

Pf = 0

change in momentum = Pf - Pi

= 0 - 3

= -3 kg m/s

HOPE IT HELPS....

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