Question

A cricket ball of mass 100g strike the hand of a player with a velocity of 20 m/s*s and is bought to rest in 0.01s calculate the force applied by the hand of the player and the acceleration of the ball.

Answer 1

u = 20 m/s

v = 0 m/s

m = 100g = 0.1kg

t = 0.01s

As we know about it that

v = u + at

0 = 20 + a*0.01

a= -2000 m/s²

So,F = ma

F = (0.1*(-2000)) = -200N

Force applied by the hand=-200 N
Acceleration of ball=-2000 m/s²