a cricket ball of mass 150 g moving at a speed of 25 mls is brought to rest by a player in 0.03s . Find the average force applied by the player .
Answers
Answered by
3
Answer:
here is the answer .. i hope it helped you...
Attachments:
Answered by
2
Given :-
A cricket ball of mass 150g moving at a speed of 25 ms^-1 is bought to rest by a player in 0.03s
To Find :-
Average force
Solution :-
We know that
v = u + at
0 = 25 + a(0.03)
0 - 25 = 0.03a
-25 = 0.03a
-25/0.03 = a
-2500/3 = a
Now
1 kg = 1000 g
150 g = 150/1000 = 0.15 kg
F = ma
F = 0.15 × -2500/3
F = 15/100 × (-2500)/3
F = -125 N
Similar questions