Question

A cricket ball of mass 150 gm moving with a speed of 30m/sec is brought to rest by 0.03 sec. Calculate the change in momentum of the ball and the average force applied by the player​

Answer 1

Explanation:

I guess the question is the rate of change in momentum

Mass=0.1kg

Initial Momentum=m×speed (u)=0.1×30=3

Final Momentum= m×rest (v)=0.1×0=0

Change in Momentum= Final-Initial =0−3=−3

Rate of change in momentum=(change in momentum)÷time taken

=(−3)÷0.03

=−100

Answer 2

Explanation:

m=0.1kg

initial momentum=0.1×30=3(u=30)

final momentum=0.1×0 =0(in rest)

momentum=0-3=-3

average force = 0.1×30=3(ma)