a cricket ball of mass 150g is moving with a velocity of 12m/s and hitted by a bat so that the ball is turned back with a velocity of 20m/s. if the duration of contact btw the ball and bat is 0.01s.then:
1. the impulse is----------------------
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impulse = F ( delta t )
Since F = ( delta p ) / ( delta t )
So impluse = ( delta p ) = 0.15 * 12 - ( - 0.15 * 20 )
= 0.15 ( 12 + 20 )
= 4.8 Ns or 4.8 Kgm/s
Since F = ( delta p ) / ( delta t )
So impluse = ( delta p ) = 0.15 * 12 - ( - 0.15 * 20 )
= 0.15 ( 12 + 20 )
= 4.8 Ns or 4.8 Kgm/s
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