Question

A cricket ball of mass 150gm moving with a speed of 12m/s is hit by a bat so that the ball is turned back with a velocity of 20m/s. calculate the impulse received by the ball.

Answer 1

impulse = change in momentum
  = m (v2 - v1)
  = 0.150 (20 + 12) = 4.8 kg-m/s

Answer 2

Answer:

✰ Question ✰

⋄A cricket ball of mass 150gm moving with a velocity of 12 m/sec is hit by a bat so that it is turned back with a velocity of 20m/s calculate impulse of ball ??

✰Given:-

⋄ Mass of cricket ball = 150gm= 150/1000=0.15kg

⋄ Initial velocity of ball (v2) = 12m/s

⋄ Final velocity (v1) = 20m/s

✰To Find :-

⋄ Impulse of ball???

✰ Solution :-

We know that

⋄ F =Δp/Δt

here, p is momentum

∴ impulse = Δp×Δt/Δt

➧ impulse = Δp

➧ Δp = mv2 - mv1

➧ Δp = m(v1 -v2)

➧ Δp = 0.15 ❪ -20 -12 ❫ (here negative motion because it rebound back)

➧ Δp= 0.15 × ❪-6❫

➧ Δp = 4.8 Ns

∴ The impluse of the ball is 4.8 Ns