Question

a cricket ball of mass 200g moving with a speed of 50m/s is brought to rest by a cricketer in 0.01 s. calculate the change in momentum

a cricket ball of mass 200g moving with a speed of 50m/s is brought to rest by a cricketer in 0.01 s. calculate the change in momentum

Answer 1

Given

• Mass = 200 g
• Initial Velocity = 50 m/s
• Final Velocity = 0 m/s
• Time = 0.01 sec

To Find

• Change in Momentum

Solution

● Here we shall first convert the mass from g to kg and then find the change in Momentum using the formula mv - mu

✭ Mass :

→ Mass = 200 g

→ 200/1000

→ Mass = 0.2 kg

━━━━━━━━━━━━━━

✭ Change in Momentum :

→ Change in Momentum = mv - mu

→ Change in Momentum = m(v-u)

→ Change in Momentum = 0.2(50-0)

→ Change in Momentum = 0.2 × 50

→ Change in Momentum = 10 kg m/s

Answer 2

Answer:

Given :-

• A cricket ball of mass 200 kg moving with a speed of 50 m/s is brought to rest by a cricketer in 0.01 seconds.

To Find :-

• What is the chance in momentum.

Formula Used :-

$\boxed{\bold{\small{Change\: in\: momentum\: =\: m(v - u)}}}$

where,

• m = Mass
• v = Final velocity
• u = Initial velocity

Solution :-

Given :

• Mass = 200 g = $\dfrac{200}{1000}$ = 0.2 kg
• Initial velocity = 50 m/s
• Final velocity = 0 m/s

According to the question by using the formula we get,

⇒ Change in momentum = 0.2 kg(50 - 0) m/s

⇒ Change in momentum = 0.2 kg(50) m/s

➠ Change in momentum = 10 kg m/s

$\therefore$ The change in momentum is 10 kg m/s .