If a+b+ c =9 and ab + bc + ca = 23, then a²+b² + c²=
A. 35
B. 58
B. 127
D. none of these
Answers
Answered by
2
Given : a + b + c = 9 and ab + bc + ca = 23
By using an algebraic identity :
(a + b + c)² = a² + b² + c² + 2ab + 2 bc + 2 ca)]
(a + b + c)² = a² + b² + c² + 2(ab + bc + ca)
(9)² = a² + b² + c² + 2(23)
81 = a² + b² + c² + 46
a² + b² + c² = 81 - 46
a² + b² + c² = 35
Hence, the value of a² + b² + c² is 35.
Option (A) 35 is correct.
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If a²+b²+c² =16, and ab + bc + ca=10, find the value of a+b+c.
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If a+b=10 and ab=16, find the value of a²– ab+b²and a²+ab+b²
brainly.in/question/15897799
Answered by
2
Answer:
Step-by-step explanation:
(a + b + c)² = a² + b² + c² + 2ab + 2 bc + 2 ca)]
(a + b + c)² = a² + b² + c² + 2(ab + bc + ca)
(9)² = a² + b² + c² + 2(23)
81 = a² + b² + c² + 46
a² + b² + c² = 81 - 46
a² + b² + c² = 35
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