Question

A cricket ball of mass 200gm moving with a speed of 40m/s is bought to rest by a player in 0.04s.
Calculate the following:
(1)Changing in momentum of the ball.
(2)Average force applied by the player​

Answer 1

Explanation:

Impulse=change in momentum=m(v−u)=0.2 (0−15)=−3Ns

Impulse=change in momentum=m(v−u)=0.2 (0−15)=−3NsAverage force=Impulse/Time=

Impulse=change in momentum=m(v−u)=0.2 (0−15)=−3NsAverage force=Impulse/Time= 0.05

Impulse=change in momentum=m(v−u)=0.2 (0−15)=−3NsAverage force=Impulse/Time= 0.053

Impulse=change in momentum=m(v−u)=0.2 (0−15)=−3NsAverage force=Impulse/Time= 0.053

Impulse=change in momentum=m(v−u)=0.2 (0−15)=−3NsAverage force=Impulse/Time= 0.053 =60 N