Question

A cricket ball of mass 500g is moving with speed of 36km/h. It is reflected back with the same speed. What is the impulse applied on it?

Answer 1

u = initial velocity = 36km/h

Convert velocity to m/s = 66 × 5/18 = 10m/s ,

v = Final velocity and it is in the opposite direction = -10m/s

Mass = 0.5kg

Impulse = mass x change in velocity

Change in velocity = Final velocity - initial velocity

= - 10 - 10 = - 20m/s

= 0.5 x (-20 )

= - 10Ns

Answer 2

Answer:

Mass is m=500g which is equal to 0.5 kg

Initial velocity is u=36km/hr

Coverting into m/s

36×5/18= 10m/s

Final velocity=v=-10m/s

-10 because it is reflected with the same speed (it is in the opposite direction)

Impulse=m(v-u)

=0.5×(-10-10)

=0.5×(-20)

=-10 Ns

Explanation: