Question

A cricket ball of mass 70 g moving with a velocity of 0.5 m / s is stopped by player in 0.5 s What is the force applied by player to stop the ball ? ( F = -0.07 newton )

Please Answer it correctly ​

Answer 1

Answer:

Question

A cricket ball of mass 70 g moving with a velocity of 0.5 m / s is stopped by player in 0.5 s What is the force applied by player to stop the ball ?

GIVEN

• mass= 70 gram = 0.07 kg
• inital Velocity= 0.5 m/sec
• final Velocity= 0
• time = 0.5 sec

To Find

Force applied to stop the ball.

Solution

⭐According to Newton's second law of motion:-

${ \underline{\boxed {\sf{f = m.a}}}}$

where

• f debotes force
• m denotes mass
• a denotes accleration

But in order to find the force we need to find the value of accleration.

⭐By First law of motion :-

${ \underline{ \boxed { \sf{v = u + at}}}}$

where

• v denotes final velocity
• u denote inital Velocity
• a denotes accleration
• t denotes time

subsitute the values in the above formula-:

$\sf{ \to \: 0 = 0.5 + a \times 0.5} \\ \\\sf {\to \: - 0.5 = 0.5a} \\ \\ \sf{ \to \: a = \frac{ -0.5}{0.5} } \\ \\ \sf{ \to \: a = - 1m/sec}$

*Note- Here minus sign in accleration denotes retardation.

subsitute the value of accleration in f= m.a

$\sf{ \to \: f = 0.07 \times ( - )1} \\ \sf{ \to \: f =(-) 0.07 \: N}$

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