Question

A cricket ball of mass 90 g moving with a velocity of 0.6 m/s is stopped by a

player in 0.5 s. What is the force applied by the player to stop the ball?​

Answer 1

Answer:

Therefore, acceleration=(v-u)/t

=(0-0.6)/0.5

=-0.6/0.5

=-6/5

=-1.2m/s^2

Therefore force =mass * acceleration

F=(90/1000)*1.2

=0.108N