Question

A cricket player catches a ball of mass 100g moving with a speed of 25m/s.if the ball is caught in 0.1 s, the average force of the blow exerted on the hands of the player is

Answer 1

Answer:

Mass of the ball, m = 100 g = 100/1000 = 0.1 kg

The initial speed of the ball, u = 0  

The final speed of the ball, v = 25 m/s

The ball is caught in time, t = 0.1 s

Using the formula,

Force * Time = Change in Momentum = m * ∆v = m * (v - u)

⇒ Force = [m * (v - u)] / time = [0.1 * (25 – 0)] / 0.1 = 25 N

Thus, the average force of the blow exerted by the ball on the hands of the player is 25 N.

Answer 2

Answer:

25 N

Formula:

F = m( v- u )/t

Explanation:

m = 100g = .1kg

v = 25m/s

t = 0.1 s

by substituting

F = 0.1(25-0)/0.1

F = 25N

The average force of the blow exerted on the hands of the player is 25N