Question

A cricket player holds a ball of mass 100g by moving his hands backward by 0.75m. If u=108km/hr find the regarding force applied by the player

Answer 1

Hey.

Here is your answer.

As , v^2- u^2=2as
and here given v=0 ; u=108km/h=30m/s
s=0.75 m
so, 0-30^2=2×a×0.75
so, a=-900/1.50= -600m/s^2

Also, m=100g =0.1 kg
and F=ma
so, regarding force =0.1×(-600)= -60N

Thanks .

Answer 2

Answer:

the answer is -60N

Explanation:

v^2- u^2=2as

and here given v=0 ; u=108km/h=30m/s

s=0.75 m

so, 0-30^2=2×a×0.75

so, a=-900/1.50= -600m/s^2

Also, m=100g =0.1 kg

and F=ma

so, regarding force =0.1×(-600)= -60N

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