Question

a cricketer ball of mass 100g moving at speed of 30ms-1 is brought to rest by a player in 0.03s. find the average force applied by the player. please explain in sequence

Answer 1

mass of the ball (m) =100g or 0.1kg
initial velocity (u) =30 m/s
time (t) = 0.03sec.
final velocity (v) = 0
Initial momentum = mu

= 0.1kg*30m/s​
= 3.0 kgm/s

Final momentum = mv (which is equal to 0, since v is zero)
Change in momentum = mv-mu

= 0 - 3.0 = -3.0 kgm/s

Average force = Change in momentum / time

= -3.0 kgms-1 /0.03s
= -100 kgm/s2
= -100 N

Answer 2

Mass = 100 gram [ we need to convert it into kg i.e., it becomes 0.1 kg]

Speed = 30 m / s

Time = 0.05 s

Initial momentum = m x v

= 0.1 x 30

= 3 kgm/s

Final momentum = m x v

= 0.1 x 0

= 0 kgm/s

(i) Change in momentum = Final momentum - Initial momentum

= ( 0 - 3 )

= - 3 kgm/s

Average Force = ( Change in momentum / Time)

= [ ( - 3 ) / ( 0.05 ) ]

= - 60 N

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