a cricketer catches a ball of mass 125g in 0.1s moving with speed 72 km per h, then he exeriences force of:
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Answered by
4
Initial velocity = 72km/h or 72*1000/3600=2m/s
Now
U=2m/s
V=0
T=0.1sec
a=(v-u)/t
= -2/0.1
= - 20m/s²
Force = mass * acceleration
Mass = 0.125kg
Force = 0.125*-20
=-2.5N
Hope you liked it plz brainliest my answer
Now
U=2m/s
V=0
T=0.1sec
a=(v-u)/t
= -2/0.1
= - 20m/s²
Force = mass * acceleration
Mass = 0.125kg
Force = 0.125*-20
=-2.5N
Hope you liked it plz brainliest my answer
Answered by
4
v=at
v=72×5/18=20m/s
v/t=a
20/0.1=200
a=200m/s2
f=ma
f=125/1000×200
=0.125×200
=25kgm/s2
v=72×5/18=20m/s
v/t=a
20/0.1=200
a=200m/s2
f=ma
f=125/1000×200
=0.125×200
=25kgm/s2
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