Question

a cricketer has a certain average for 10 innings.In the 11th innings,he scored 108 runs, thereby increasing his average by 6 runs.His new average is?

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Answer 1

AnswEr :

Let the Average After 10th Inning be n.

• According to the Question Now :

$\implies \tt\underbrace{10 \: innings}_{ \large(10 \times n)} +\underbrace{11th \: inning}_{ \large108} = \underbrace{After \: 11th \: inning}_{ \large11 \times (n + 6)}$

$\implies \tt10n + 108 = 11(n + 6)$

$\implies \tt10n + 108 = 11n + 66$

$\implies \tt108 - 66 = 11n - 10n$

$\implies \boxed{ \tt n = 42}$

$\rule{300}{1}$

• Average of Cricketer after 11th Inning :

$\longrightarrow\tt Average_{11th \:Inning}=(n+6)$

$\longrightarrow\tt Average_{11th \:Inning}=(42+6)$

$\longrightarrow\red{\tt Average_{11th \:Inning}=48}$

⠀

∴ Average after 11th Inning will be 48.

Answer 2

Answer:

$\huge\underline\mathbb\green{Answer:}$

Let the average after 10 innings be Y

According to question:-

(Y × 10)+ 108 = 11 × (Y+6)

$\implies$10Y + 108 = 11Y + 66

$\implies$10Y - 11Y = 66 - 108

$\implies$-Y =- 42

$\implies$★ Y = 42

After 11th innings,his new average will be:-

New average = Y + 6

New average = 42 + 6

★ New average = 48

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