Question

A cricketer has completed 14 innings and his average is 30 runs. How many runs must his next innings so as raise his average to 32?​

Answer 1

Average = total runs / no.of innings = 32 

So, total = Average x no.of innings = 32 x 10 = 320.

 

Now increase in avg = 4runs. So, new avg = 32+4 = 36runs 

Total runs = new avg x new no. of innings = 36 x 11 = 396 

Runs made in the 11th inning = 396 - 320 = 76

Answer 2

Answer:

60 runs must his next innings so as raise his average to 32.

Step-by-step explanation:

Given,cricketer has completed 14 innings and his average run is 30.

So,in 14 innings his total run $= 14 \times 30 = 420$

Let, x runs must his next innings so as raise his average to 32.

According to question,

$\frac{420 + x}{15} = 32 \\ 420 + x = 15 \times 32 \\ 420 + x = 480 \\ x = 480 - 420 \\ x = 60$

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

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