a cricketer Hits a ball with a velocity 25m/s at 60° above horizontal.how far above the ground it passes over a fielder 50m from the bat ?
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The horizontal velocity of the ball will be vcosø or 25cos60 this amount will be 12.5m/s along X axis
Then
50/12.5
=4seconds before the ball is thrown by the cricketer.
The vertical height will be h(4)=g/2(4)²+25sin60(4)
=-4.9(16)+21.25(4)
=8.2025m as height of the ball after 4sec
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