Question

A crosscutting machine requires a force of 100kN. The area of the hydraulic cylinder is 200cm2. What must be the minimum pressure in the cylinder to exert this force on the piston?​

Answer 1

Explanation:

We know that, Pressure=

Area

Force

⇒Pressure=

10

2

=0.2Ncm

−2

Now, Pressure=0.2

Again, Force=Pressure×Area

Force=0.2×100=20N