A crowbar of length 1 m is used to lift a heavy load of 800N by placing a fulcrum at a distance of 10 cm from it. An effort of 200 N is applied at the other end. Calculate its efficiency.
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Explanation:
Length of crow bar = 2m
length of load arm = 0.1M
length effort arm = length of crow bar -length of load arm
=2−0.1=1.9m
so, velocity ratio = length of effort arm/length of load arm = 1.9/0.1 = 19
use formula, velocity ratio = load/effort
19 = 100kgf/effort
effort = 100/19= 5.26 kgf
hence,5.26 effort is required.
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