A crystal formula ab3 has a ions at cube corners, and b at edge centres of cube, find cordination numbers of a and b
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The options for this question are missing:
(A) 6 and 6
(B) 2 and 6
(C) 6 and 2
(D) 8 and 8
The correct answer for this question is (C) 6 and 2
Co - ordination of cation/ Co - ordination no of anion
= charge of cation/ charge of anion = 3/1 = 3
(coordination number of A = 6)
Now co-ordination no of A is shown so B is 2
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