Chemistry, asked by dachampiong1, 7 months ago

A crystal of copper sulfate was placed in a beaker of water. After sometime it had disappeared and the water had turned blue. Which two processes had taken place

a) Melting and evaporation
b) Melting and diffusion
c) Dissolving and evaporation
d) Dissolving and diffusion

Other:

Answers

Answered by rudrakshikakkar2007
1

Answer:

c) Dissolving and diffusion

Explanation:

This is due to the movement of water particles. due to this, the copper sulphate particles and water molecules get mix with each other by the process of diffusion. due to this diffusion, when a crystal of copper sulphate is placed at the bottom of a beaker containing water , the water slowly turns blue.

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Answered by urja79
1

Answer:

due to this, the copper sulphate particles and water molecules get mix with each other by the process of diffusion. due to this diffusion, when a crystal of copper sulphate is placed at the bottom of a beaker containing water , the water slowly turns blue.

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