Question

A cube-1 By A cube-2a+2 by a

Answer 1

Hey here is your answer
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$= \frac{ {a}^{3} - 1 }{ {a}^{3} - 2a + \frac{2}{a} } \\ = \frac{ a \times ({a}^{3} - 1) }{ {a}^{4} - 2 {a}^{2} + {2}} \\ = \frac{ ({a}^{4} - a) }{ {a}^{4} - 2 {a}^{2} + {2}}$
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