A cube minus 8 b cube minus 64 c cubeminus 24 ABC
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Answered by
2
Hi friend!!
Given,
a³-8b³-64c³-24abc
=a³+(-2b)³+(-4c)³-3(a)(-2b)(-4c)
We know that, x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx)
=(a-2b-4c)(a²+4b²+16c²+2ab-8bc+4ac)
I hope this will help you ;)
Given,
a³-8b³-64c³-24abc
=a³+(-2b)³+(-4c)³-3(a)(-2b)(-4c)
We know that, x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx)
=(a-2b-4c)(a²+4b²+16c²+2ab-8bc+4ac)
I hope this will help you ;)
Answered by
0
a^3 -8b^3 - 64c^3- 24abc
=a^3 - (2b)^3 - (4c)^3 -3*a*2b*4c
=(a-2b-4c)[a^2-(2b)^2 - (4c)^2+2ab +8bc+4ca]
=a^3 - (2b)^3 - (4c)^3 -3*a*2b*4c
=(a-2b-4c)[a^2-(2b)^2 - (4c)^2+2ab +8bc+4ca]
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