Thh h.c.f of two numbers is 9 and their l .c.m is 270 . If one number is five times of the h.c.f find the other number
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Hcf 9
Lcm 270
One no.. 45
Other no..= lcm * hcf/ one no
= 270*9/45
= 54
Lcm 270
One no.. 45
Other no..= lcm * hcf/ one no
= 270*9/45
= 54
Answered by
0
hcf=9
1st no.-9*5-45
hcf*lcm=1st no.*2nd no.
=>9*270=45*2nd no.
=>2nd no.=9*270รท45
=2nd no.=54
1st no.-9*5-45
hcf*lcm=1st no.*2nd no.
=>9*270=45*2nd no.
=>2nd no.=9*270รท45
=2nd no.=54
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