A cube of 11 cm edge is immersed completely in a rectangular vessel containing water. If the dimensions of the base of the vessel are 15cm x 12 cm, find the rise in the water level in centimeters correct to 2 decimal places, assuming that no water overflows.
Answers
Dimension of the base of the rectangular vessel = 15 cm × 12 cm
Let the rise in water level in the rectangular vessel be h cm.
Since, the cube is completely un messed in the rectangular vessel,
∴ Volume of water displaced in the rectangular vessel = Volume of the cube
⇒ 15 cm × 12 cm × h = (11 cm)3
⇒ h ≈ 7.39 cm
Thus, the rise in water level in the rectangular vessel is 7.39 cm approximately.
Given :- A cube of 11 cm edge is immersed completely in a rectangular vessel containing water . if the dimension of the base of the vessel are 15*12cm find the rise in water level to 1 decimal place assuming no water overflows ?
Solution :-
we have,
→ Edge of cube = 11 cm.
so,
→ volume of cube = (Edge)³ = (11)³ = 1331 cm³.
also, given,
→ the dimension of the base of the vessel are 15 * 12cm .
Let us assume that the rise in the level of water in the vessel is upto height h cm.
we know that,
- Volume of cube = Volume of water rises .
- volume of cuboid = Length × Breadth × Height
therefore,
→ 15 * 12 * h = 1331
→ 180h = 1331
→ h = (1331/180)
→ h ≈ 7.39 (Ans.)
Hence, The rise in water level to height of 7.39 cm.
Learn more :-
from a solid cylinder whose height is 3.6 cm and diameter 2.1 CM a conical cavity of the same height and the same diamet...
https://brainly.in/question/24336372
A hemisphere of radius 21 cm is completely filled with milk. There is a hole in
the bottom whose radius is 0.1 cm. If ra...
https://brainly.in/question/25349591