Question

A cube of 4cm has ben painted on its surfaces in such a way that two opposite surfaces have been painted blue

Answer 1

Answer:

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volume of painted box= (4×4)2+2×4×2=48cm^3

volume of unpainted box=64-52=12cm^3

number of unpainted cubes 12.

number of cubes of red 2×4×2+4×3=28-14=14 red cubes

Answer 2

$\huge{\mathcal{\blue{HeY!}}}$

Two adjacent surfaces have been painted red and if cut these surface into 1 cm length then we would get many small cube of side 1 cm, and so one surface of big cube will form 4∗4=16 surfaces of small cube.

Now as per given statement in question, "two adjacent surfaces have been painted red" That means adjacent surface will also form 4∗4=16 small cube with red paint.

So total cube of red colour might be 16+16=32 .

But the four cubes are common in both the red colour surfaces.

Thus, total cubes having at least red colour on its surfaces will be 32−4=28.

Answer is 28.....✌✌

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