Question

A cube of each side 10 cm is placed inside a liquid. Calculate the thrust exerted by the liquid on any face, if the pressure at the face of the cube is 5Pa.

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Answer 1

Answer:

5×10^-3N

Explanation:

F=PA

so

F=5×10×10^-4

=5×10^-3N

Answer 2

Solution :-

Given :-

$\bf \: P = 5Pa$

Formula :-

$\sf \: Area \: of \: cube = 10cm × 10cm$

$\sf= 100cm^2 = 100 × 10 { }^{ - 4} \: m^2$

Therefore ,

$\sf∴ Thrust \: Exerted \: by \: the \: liquid \: on \: face \: of \: the \: cube$

$\: \: \: \: \: \: \: \: \: \: \: \sf \: F = P × A$

$\sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 5 × 100 ×10 {}^{ - 4}$

$\sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 5 × 10 {}^{ - 2} \: N$

⭐ Hope you understand this answer mate ⭐