a cube of each side 5 cm is placed inside a liquid.The pressure at the centre of one face of cube is 10pa.Calculate the thrust exerted by liquid on this face
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Answer:
2.5×10-2N
Explanation:
Given, pressure P=10Pa,
Area of face A=5cm×5cm=5100m×5100m
=25×10−4m2
The thrust exerted by the liquid on the face.
F=P×A=10Pa×(25×10−4)m2=2.5×10−2N.
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