Physics, asked by cviie102007, 1 month ago

a cube of each side 5 cm is placed inside a liquid.The pressure at the centre of one face of cube is 10pa.Calculate the thrust exerted by liquid on this face​

Answers

Answered by avyasahu98
1

Answer:

2.5×10-2N

Explanation:

Given, pressure P=10Pa,

Area of face A=5cm×5cm=5100m×5100m

=25×10−4m2

The thrust exerted by the liquid on the face.

F=P×A=10Pa×(25×10−4)m2=2.5×10−2N.

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