Question

A cube of edge 14cm. is surmounted by a cone of maximum diameter and height 14cm Find the
total surface area of the shape so formed.
​

Answer 1

Answer:

6 X 14^2= 6X196=1176 we get 1176 sq.cm

Answer 2

Answer:

Surface area of the shape so formed  is 1520 square centimeter .

Step-by-step explanation:

Given as :

The measure of each edge of cube = 14 cm

The cube is surmounted by cone

The height of cone = h = 14 cm

The diameter of cone = d = 14 cm

So, The radius of cone = r = $\dfrac{d}{2}$ = $\dfrac{14}{2}$

Or, r = 7 cm

∵  Total surface area of cone = π × r × l  + π × r²

where l is the slant height

l = $\sqrt{7^{2} + 14^{2} }$

Or, l = $\sqrt{245}$ = 15.65  cm

So, slant height = l = 15.65 cm

Or, Total surface area of cone = 3.14 × 7 × 15.65  + 3.14 × 7²

Or, Total surface area of cone = 343.987 + 153.86

Or, Total surface area of cone = 497.847  cm²

Again

Total surface area of cube = 6 × side²

Or, Total surface area of cube = 6 × 14²

Or, Total surface area of cube = 1176 cm²

Again

The circle thus formed , so the area of circle formed = 3.14 × 7² = 153.86 cm²

The area of circle = 153.86 cm²

Surface area of the shape so formed  = (surface area of cone - area of circle) + surface area of cone

Or, Surface area of the shape so formed  = (1176 cm² -  153.86 cm² ) + 497.847  cm²

Or, Surface area of the shape so formed  = 1519.9 cm²

Hence, Surface area of the shape so formed  is 1520 square centimeter . Answer