. a cube of mass 1kg with each side of 1cm is lying on the table. find the pressure exerted by the block on the table. take g=10 m/s2
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9
Pressure = Force / Area
= mg / A
= (1 kg × 10 m/s²) / (10⁻⁴ m²)
= 10⁵ pascals
Pressure exerted by block on the table is 10⁵ pascals
= mg / A
= (1 kg × 10 m/s²) / (10⁻⁴ m²)
= 10⁵ pascals
Pressure exerted by block on the table is 10⁵ pascals
Answered by
0
Answer: 10^5 pascals or N/m^2
Step-by-step explanation:
Mass of the cube, m = 1 kg
The area = 1 cm x 1 cm
= 1 cm^2
= 1 *(1/100 m)^2
= 1/10000 m^2
Thrust = F = m x g
=1 kg x 10 m/s^2
=10 N
Pressure = Thrust/area
=10/1/10000
=10 x 10000
= 100000 N/m^2
= 100000 pascal
So the pressure exerted is 100000 pascals or 10^5 pascal
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