Physics, asked by ajaygautamjhajjar, 11 months ago

A cube of side 20 cm is kept in a region as shown in the figure. Ai
exists in the region such that the potential at
point is given by V = 10x + 5, v is in volt and x in m.find electric field and electric flux through cube​

Answers

Answered by CarliReifsteck
6

Given that,

Side of cube = 20 cm

Potential V =10x+5

We need to calculate the value of \dfrac{dV}{dx}

Using potential

V=10x+5

On differentiating w. r. to x

\dfrac{dV}{dx}=10+0

We need to calculate the electric field

Using formula of electric field

E=-\dfrac{dV}{dx}

E=-10i\ N/C

The electric field is constant in negative x-direction

The flux enter in the cube will be same as flux come out through the cube.

So, The net flux will be zero.

Hence, The electric field is -10i N/C.

The net flux will be zero

Attachments:
Answered by prabhas24480
2

Given that,

Side of cube = 20 cm

Potential V =10x+5

We need to calculate the value of \dfrac{dV}{dx}

Using potential

V=10x+5

On differentiating w. r. to x

\dfrac{dV}{dx}=10+0

We need to calculate the electric field

Using formula of electric field

E=-\dfrac{dV}{dx}

E=-10i\ N/C

The electric field is constant in negative x-direction

The flux enter in the cube will be same as flux come out through the cube.

So, The net flux will be zero.

Hence, The electric field is -10i N/C.

The net flux will be zero

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