a cube of side 5 cm is cut into as many 1 cm cubes as possible. what is the ratio of the surface area of the original cube to that of the sum of the surface areas of the smaller cubes?
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Answered by
66
let the number of smaller cubes = n
we have to use,
volume of original cubes = n × volume of smaller cubes
(5cm)³ = n (1cm)³
125 cm³ = n × 1cm³
n = 125
hence, number of smaller cubes = 125
now, sum of surface area of all smaller cubes = 125 × 6 (1 cm)²
and surface area of original cube = 6 ( 5 cm)²
surface area of original cube/ sum of surface area of smaller cubes = 6(5cm)²/125 × 6(1cm)² = 25/125 = 1/5
hence, answer is 1 : 5
we have to use,
volume of original cubes = n × volume of smaller cubes
(5cm)³ = n (1cm)³
125 cm³ = n × 1cm³
n = 125
hence, number of smaller cubes = 125
now, sum of surface area of all smaller cubes = 125 × 6 (1 cm)²
and surface area of original cube = 6 ( 5 cm)²
surface area of original cube/ sum of surface area of smaller cubes = 6(5cm)²/125 × 6(1cm)² = 25/125 = 1/5
hence, answer is 1 : 5
Answered by
4
Answer:
25:1
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