a cube of side 5cm contain a sphere toughing side find the volume of gap between
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Side of Cube = Diameter of Sphere
So , radius of sphere = 5/2 cm
Volume of cube = 5³ = 125 cm³
Volume of sphere =

Volume of gap between = 125 - 1375/21
= ( 2625 - 1375 )/ 21
= 1250/21 cm³
= 59.523 cm³
Side of Cube = Diameter of Sphere
So , radius of sphere = 5/2 cm
Volume of cube = 5³ = 125 cm³
Volume of sphere =
Volume of gap between = 125 - 1375/21
= ( 2625 - 1375 )/ 21
= 1250/21 cm³
= 59.523 cm³
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