if one zero of 2x²-3x+k is reciprocal the other.find the value of k
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Answered by
7
Let the zeros of given polynomial
2x²-3x+k are ç and ß
we know that :-
now product of zeros = c/a
where c is the constant term and a is coffecient of x²
thus çß = k/2 ---------(2)
Now it is given that ç = 1/ß ---
substitute it in equation 2
we get k = 2
2x²-3x+k are ç and ß
we know that :-
now product of zeros = c/a
where c is the constant term and a is coffecient of x²
thus çß = k/2 ---------(2)
Now it is given that ç = 1/ß ---
substitute it in equation 2
we get k = 2
Answered by
4
hey friends ☺
Given one zero of of polynomial is k
then it's raciprocal is 1/k
as you know the product of two zeroes is
@×bita =constant term/cofficient of x²
k×1/k=k/2
1=k/2
2=k.
Answer is 2. ..
hope it helps you .
#Rajukumar111
Given one zero of of polynomial is k
then it's raciprocal is 1/k
as you know the product of two zeroes is
@×bita =constant term/cofficient of x²
k×1/k=k/2
1=k/2
2=k.
Answer is 2. ..
hope it helps you .
#Rajukumar111
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